document.write( "Question 285941: how many ounces of a 40% alcohol solution must be mixed with 5 ounces of a 45% alcohol solution to make a 41% alcohol solution? \n" ); document.write( "

Algebra.Com's Answer #207338 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(ounces of alcohol in final solution)/(total ounces of final solution) = 41%
\n" ); document.write( "Let $\"x\"$ = ounces of 40% alcohol solution needed
\n" ); document.write( " $\".45%2A5+=+2.25\"$ ounces of alcohol in 45% solution
\n" ); document.write( "---------------------------------------------------
\n" ); document.write( " $\"%28.4x+%2B+2.25%29%2F%28x+%2B+5%29+=+.41\"$
\n" ); document.write( " $\".4x+%2B+2.25+=+.41%2A%28x+%2B+5%29\"$
\n" ); document.write( " $\".4x+%2B+2.25+=+.41x+%2B+2.05\"$
\n" ); document.write( " $\".01x+=+2.25+-+2.05\"$
\n" ); document.write( " $\".01x+=+.2\"$
\n" ); document.write( " $\"x+=+20\"$
\n" ); document.write( "20 ounces of a 40% alcohol solution are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"%28.4x+%2B+2.25%29%2F%28x+%2B+5%29+=+.41\"$
\n" ); document.write( " $\"%28.4%2A20+%2B+2.25%29%2F%2820+%2B+5%29+=+.41\"$
\n" ); document.write( " $\"%288+%2B+2.25%29%2F25+=+.41\"$
\n" ); document.write( " $\"10.25+=+25%2A.41\"$
\n" ); document.write( " $\"10.25+=+10.25\"$
\n" ); document.write( "OK \n" ); document.write( "

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