document.write( "Question 285902: the perimeter of a rectangle is twice the sum of its length and its width, the perimeter is 40 meters and te length is 2 meters more than twice its width what is the length \n" ); document.write( "
Algebra.Com's Answer #207326 by mgmoeab(37)\"\" \"About 
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1).- P = 2(W + L)-------------OR-------------- P= 2W +2L (distributing)\r
\n" ); document.write( "\n" ); document.write( "where:
\n" ); document.write( "p= perimeter
\n" ); document.write( "w= width
\n" ); document.write( "l= length\r
\n" ); document.write( "\n" ); document.write( "They tell you that \"the length is 2 meters more than twice it width\"\r
\n" ); document.write( "\n" ); document.write( "2).- L = 2 + 2W\r
\n" ); document.write( "\n" ); document.write( "If we substitute (2) in (1), then:\r
\n" ); document.write( "\n" ); document.write( "P = 2W + 2 ( 2 + 2W)
\n" ); document.write( "P = 2W + 4 + 4W
\n" ); document.write( "P = 6W + 4\r
\n" ); document.write( "\n" ); document.write( "We also know that the perimeter is 40 meters, so:
\n" ); document.write( " P = 40 = 6W + 4\r
\n" ); document.write( "\n" ); document.write( "Solving for W, you get:\r
\n" ); document.write( "\n" ); document.write( "40 = 6W + 4
\n" ); document.write( "36 = 6W\r
\n" ); document.write( "\n" ); document.write( "W = 6.\r
\n" ); document.write( "\n" ); document.write( "But we want to know what L equals. We go back to equation 2 and subtitue W =6.\r
\n" ); document.write( "\n" ); document.write( "L = 2 + 2(6)\r
\n" ); document.write( "\n" ); document.write( "L= 14\r
\n" ); document.write( "\n" ); document.write( "WHICH IS TRUE..\r
\n" ); document.write( "\n" ); document.write( "P = 2(6) + 2 (14)
\n" ); document.write( "P = 12 + 28
\n" ); document.write( "P = 40
\n" ); document.write( " \n" ); document.write( "
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