document.write( "Question 285871: log3(3x)=log3x+log3(4-x) \n" ); document.write( "
Algebra.Com's Answer #207316 by user_dude2008(1862)\"\" \"About 
You can put this solution on YOUR website!
log3(3x)=log3x+log3(4-x)\r
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\n" ); document.write( "\n" ); document.write( "log3(3x)=log3[x(4-x)]\r
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\n" ); document.write( "\n" ); document.write( "3x=x(4-x)\r
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\n" ); document.write( "\n" ); document.write( "3x=4x-x^2\r
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\n" ); document.write( "\n" ); document.write( "x^2-4x+3x=0\r
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\n" ); document.write( "\n" ); document.write( "x^2-x=0\r
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\n" ); document.write( "\n" ); document.write( "x(x-1)=0\r
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\n" ); document.write( "\n" ); document.write( "x=0 or x-1=0\r
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\n" ); document.write( "\n" ); document.write( "x=0 or x=1\r
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\n" ); document.write( "\n" ); document.write( "Answer: only solution is x=1
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