document.write( "Question 285835: a chemist need 80 millitiltes of 25% solution but only has 22% and 30% solutions available How many milliliters of each that should be mixed to get the desired solution number of mill of 22% and the number of mill for 30% \n" ); document.write( "

Algebra.Com's Answer #207269 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
A chemist need 80 millitiltes of 25% solution but only has 22% and 30% solutions available.
\n" ); document.write( " How many milliliters of each that should be mixed to get the desired solution number of mill of 22% and the number of mill for 30%.
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.22x + 0.30(80-x) = 0.25(80)
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "22x + 30*80 - 30x = 25*80
\n" ); document.write( "-8x = -5*80
\n" ); document.write( "x = 50 milliliters (amt. of 22% solution needed in the mixture)
\n" ); document.write( "---
\n" ); document.write( "80-x= 30 milliliters (amt. of 30% solution needed in the mixture)
\n" ); document.write( "==============================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "

\n" );