document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285822>Question 285822</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one root of quadratic equation 3x square - 10 x +3=o is 1/3.find other root </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207252 by </B><A HREF=/tutors/aboutme.mpl?userid=Grinnell><B>Grinnell(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Grinnell><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In factoring we break the polynomial down and then 'hit or miss'\r<BR>\n" );
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document.write( "3x^2-10x+3=0\r<BR>\n" );
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document.write( "(3x-?)(x-??) = 0\r<BR>\n" );
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document.write( "we know that product of (?) and (??) equals positive three. (-something times -something=positive something!)\r<BR>\n" );
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document.write( "how about for starters one and three?\r<BR>\n" );
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document.write( "let 1=?, let 3 =??, substitute--this works. THE OTHER ROOT IS THREE WHICH IS THE ANSWER!\r<BR>\n" );
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document.write( "(understand for the first root 3x-1 = 0, yes x equals 1/3.\r<BR>\n" );
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document.write( "We solved for the other.   </SPAN>\n" );
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