document.write( "Question 285732: the perimeter of a rectangle is 148 m. The length is 2 m more than twice the width. what is the dimensions \n" ); document.write( "
Algebra.Com's Answer #207250 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=2W+2 \n" ); document.write( "148=2(2W+2)+2W \n" ); document.write( "148=4W+4+2W \n" ); document.write( "148=6W+4 \n" ); document.write( "6W=148-4 \n" ); document.write( "6W=144 \n" ); document.write( "W=14/6 \n" ); document.write( "W=24 ANS. FOR THE WIDTH. \n" ); document.write( "L=2*24+2=48=2=50 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "148=2*50+2*24 \n" ); document.write( "148=100+48 \n" ); document.write( "148=148 \n" ); document.write( " |