document.write( "Question 285732: the perimeter of a rectangle is 148 m. The length is 2 m more than twice the width. what is the dimensions \n" ); document.write( "
Algebra.Com's Answer #207250 by checkley77(12844)\"\" \"About 
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P=2L+2W
\n" ); document.write( "L=2W+2
\n" ); document.write( "148=2(2W+2)+2W
\n" ); document.write( "148=4W+4+2W
\n" ); document.write( "148=6W+4
\n" ); document.write( "6W=148-4
\n" ); document.write( "6W=144
\n" ); document.write( "W=14/6
\n" ); document.write( "W=24 ANS. FOR THE WIDTH.
\n" ); document.write( "L=2*24+2=48=2=50 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "148=2*50+2*24
\n" ); document.write( "148=100+48
\n" ); document.write( "148=148
\n" ); document.write( "
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