document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285807>Question 285807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that in any triangle ABC the length x of the median from C is given by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%281%2F2%29+sqrt%282a%5E2%2B2b%5E2-c%5E2%29 ALIGN=MIDDLE  ALT=\"x=%281%2F2%29+sqrt%282a%5E2%2B2b%5E2-c%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I know it has to do with the law of cosines: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cos%28C%29+=+%28a%5E2%2Bb%5E2-c%5E2%29%2F2ab ALIGN=MIDDLE  ALT=\"cos%28C%29+=+%28a%5E2%2Bb%5E2-c%5E2%29%2F2ab\"   DISABLED_style= \"max-width:90%; height:auto;\" > but I'm not sure how to simplify it to this other equation. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207231 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207231\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=(1/2)sqrt(2a^2+b^2-c^2)<BR>\n" );
document.write( "2x=sqrt(2a^2+2b^2-c^2)<BR>\n" );
document.write( "4x^2= (2a^2+2b^2-c^2)<BR>\n" );
document.write( "x^2= (2a^2+2b^2-c^2)/4<BR>\n" );
document.write( "x^2=(a^2+b^2-c^2)/2<BR>\n" );
document.write( "so to be equal x^2 must be ab<BR>\n" );
document.write( "can you take it from here? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );