document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285614>Question 285614</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle?\r<BR>\n" );
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document.write( "I would like to see how to solve the problem in steps, if possible. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #207198 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=207198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let the width of the 1st rectangle be W. Then its length = 4W, since its length is 4 times its width\r<BR>\n" );
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document.write( "The width and length of the 2nd rectangle are W  + 2, and 4W + 5, respectively, since the second rectangle is 2 centimeters wider and 5 centimeters longer than the 1st.\r<BR>\n" );
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document.write( "The area of the 1st rectangle is then: W*4W, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4W%5E2 ALIGN=MIDDLE  ALT=\"4W%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the area of the 2nd rectangle is (W + 2)(4W + 5 ), or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4W%5E2+%2B+13W+%2B+10%29 ALIGN=MIDDLE  ALT=\"4W%5E2+%2B+13W+%2B+10%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Since the area of the 2nd rectangle is 270 square centimeters greater than the area of the 1st rectangle, then we’ll have: \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4W%5E2+%2B+270+=+4W%5E2+%2B+13W+%2B+10 ALIGN=MIDDLE  ALT=\"4W%5E2+%2B+270+=+4W%5E2+%2B+13W+%2B+10\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4W%5E2+-+4W%5E2+-+13W+=+10+-+270 ALIGN=MIDDLE  ALT=\"4W%5E2+-+4W%5E2+-+13W+=+10+-+270\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "- 13W = - 260\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W+=+%28-260%29%2F-13+=+20 ALIGN=MIDDLE  ALT=\"W+=+%28-260%29%2F-13+=+20\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, since W, or width = 20, then the dimensions of the 1st rectangle are: W, or width = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2820%29 ALIGN=MIDDLE  ALT=\"highlight_green%2820%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm, and L, or length = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2880%29 ALIGN=MIDDLE  ALT=\"highlight_green%2880%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm ------> 4W, or 4(20)\r<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "Width of 1st rectangle = 20 cm<BR>\n" );
document.write( "Length of 1st rectangle = 4(20) = 80 cm\r<BR>\n" );
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document.write( "Area of 1st rectangle = 20 * 80 = 1,600 sq centimeters\r<BR>\n" );
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document.write( "Width of 2nd rectangle = 22 cm (20 + 2)<BR>\n" );
document.write( "Length of 2nd rectangle = 85 cm (4*20 + 5)\r<BR>\n" );
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document.write( "Area of 2nd rectangle = 22 * 85 = 1,870 sq centimeters\r<BR>\n" );
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document.write( "Area of 2nd rectangle (1,870 sq centimeters) is 270 sq centimeters greater than area of 1st rectangle (1,600 sq centimeters).\r<BR>\n" );
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document.write( "Send comments and “thank yous” to MathMadEzy@aol.com </SPAN>\n" );
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