document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31796>Question 31796</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help? and check my answer to see if im doing this right?<BR>\n" );
document.write( "For the function y =  x^2 - 4x - 5, perform the following tasks:<BR>\n" );
document.write( "(1)Put the function in the form y = a(x - h)^2 + k.<BR>\n" );
document.write( "I got the answer: y = (x-2)^2 - 9\r<BR>\n" );
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document.write( "What is the line of symmetry?\r<BR>\n" );
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document.write( "I got the answer: x = 2\r<BR>\n" );
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document.write( "Graph the function using the equation in part (1).  Explain why it is not necessary to plot points to graph when using y = a (x – h)^2 + k.\r<BR>\n" );
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document.write( "how does this graph compare to the graph of y = x^2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20713 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE MY COMMENTS BELOW..AND THE ADDDITIONAL EXAMPLE GIVEN BELOW<BR>\n" );
document.write( "Can someone help? and check my answer to see if im doing this right?<BR>\n" );
document.write( "For the function y = x^2 - 4x - 5, perform the following tasks:<BR>\n" );
document.write( "(1)Put the function in the form y = a(x - h)^2 + k.<BR>\n" );
document.write( "I got the answer: y = (x-2)^2 - 9......................OK<BR>\n" );
document.write( "What is the line of symmetry?<BR>\n" );
document.write( "I got the answer: x = 2...OK..VERY GOOD<BR>\n" );
document.write( "Graph the function using the equation in part (1).<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+600%2C+600%2C+-6%2C+6%2C+-10%2C+10%2C+%28%28x-2%29%5E2-9%29%2C%28x-2%29%2F0.000001%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " Explain why it is not necessary to plot points to graph when using y = a (x – h)^2 + k.<BR>\n" );
document.write( " YOU CAN DRAW LINE OF SYMMETRY.,PLOT VERTEX AND SKETCH THE GRAPH ON EITHER SIDE OF LINE OF SYMMETRY BY SMOOTH LINES NOTING,THE X INTERCEPTS OF -1 AND 5 AND  THAT Y TENDS TO INFINITY AS X TENDS TO INFINITY.<BR>\n" );
document.write( "how does this graph compare to the graph of y = x^2?<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+600%2C+600%2C+-6%2C+6%2C+-10%2C+10%2C%28%28x-2%29%5E2-9%29%2C+x%5E2%2C%28x-2%29%2F0.000001%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "---------------------------------------------------------------------------<BR>\n" );
document.write( "SEE THE FOLLOWING EXAMPLE WHICH IS ALMOST SAME AS YOUR PROBLEM AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK.<BR>\n" );
document.write( "Y=X^2-2X-3=X^2-2*X*1+1^2-1-3=(X-1)^2-1-3=(X-1)^2-4=0<BR>\n" );
document.write( "X INTERCEPT IS OBTAINED BY PUTTING Y=0....WE GET<BR>\n" );
document.write( "X^2-2X-3=0=X^2-3X+X-3=X(X-3)+1(X-3)=(X-3)(X+1)=0...SO..X=3 OR -1...<BR>\n" );
document.write( "Y INTERCEPT IS GOT BY PUTTING X =0...WE GET<BR>\n" );
document.write( "Y=0-0-3=-3<BR>\n" );
document.write( "SEE THE GRAPH BELOW ......<BR>\n" );
document.write( "graph( 500, 500, -10, 20, -20, 20,x^2-2x-3 )<BR>\n" );
document.write( "THE AXIS IS X=1 AS YOU CAN SEE FROM THE GRAPH<BR>\n" );
document.write( "ONE POINT SYMMETRIC TO Y INTERCEPT??NO...SYMMETRIC TO AXIS IT IS......(-1,3)<BR>\n" );
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document.write( "I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k.<BR>\n" );
document.write( "MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE.<BR>\n" );
document.write( "Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE<BR>\n" );
document.write( "y=a(x-h)^2+k.<BR>\n" );
document.write( "WE GET A=1 AND K=-16<BR>\n" );
document.write( "I have to find the line of symmetry.<BR>\n" );
document.write( "X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12<BR>\n" );
document.write( "(h,k)=vertex I think you use complete the square technique.<BR>\n" );
document.write( "YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX<BR>\n" );
document.write( "THE GRAPH WILL LOOK LIKE THIS<BR>\n" );
document.write( "graph( 500, 500, -10, 20, -20, 20, x^2-2x-15 )<BR>\n" );
document.write( "Please help. thanks </SPAN>\n" );
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