document.write( "Question 34420: Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #20707 by hydromojo(20)\"\" \"About 
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Lets say Walt puts $'X' @8%. the remaining would be $(9000-X)\r
\n" ); document.write( "\n" ); document.write( "Interest calculation = amount * (rate/100)0*time(in yrs in this case)\r
\n" ); document.write( "\n" ); document.write( "So, for the 8% investment
\n" ); document.write( "Interest = X * (8/100) * 1 = $.08X ........#1\r
\n" ); document.write( "\n" ); document.write( "for the 9% investment
\n" ); document.write( "Interest = (9000-X) * (9/100) * 1 = 810 - 0.09X ...........#2\r
\n" ); document.write( "\n" ); document.write( "The total interest is given as $770, so adding #1 & 2, we get\r
\n" ); document.write( "\n" ); document.write( ".08X + 810 - .09X = 770\r
\n" ); document.write( "\n" ); document.write( "solve this for X, and you get it to be $4000
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