document.write( "Question 285627: The perimeter of a rectangle is 52 inches. If the length of the rectangle is 9 inches less than 4 times the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #207058 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
there are definetly similar problems to these in the rectangle section you should review that section before posting yours.
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "\"L=4W-9\"
\n" ); document.write( "substitute and solve
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "\"52=2%284W-9%2BW%29\"add
\n" ); document.write( "\"52=2%285W-9%29\"distribute
\n" ); document.write( "\"52=%2810W-18%29\"add
\n" ); document.write( "\"52%2B18=%2810W%29\"
\n" ); document.write( "\"70=10W\"divide
\n" ); document.write( "\"highlight%287=W%29\"
\n" ); document.write( "\"L=4W-9\"
\n" ); document.write( "\"L=4%287%29-9\"multiply
\n" ); document.write( "\"L=28-9\"subtract
\n" ); document.write( "\"highlight%28L=19%29\"
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