document.write( "Question 285614: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle?\r
\n" ); document.write( "\n" ); document.write( "I would like to see how to solve the problem in steps, if possible. Thank you!
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Algebra.Com's Answer #207047 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
\"A=LW\", \"A=5L\" because w=4l. A=LW is the first rectangle
\n" ); document.write( "\"W=4L\" \"A rectangle is 4 times as long as it is wide.\"
\n" ); document.write( "\"X=L%2B5\" \"Y=W%2B2\" \"A second rectangle is 5 centimeters longer and 2 centimeters wider than the first.\"
\n" ); document.write( "\"XY=A%2B270\" \"The area of the second rectangle is 270 square centimeters greater than the first\" this is the second rectangle.
\n" ); document.write( "so now wee need to substitute to be able to solve for \"L\"
\n" ); document.write( "\"XY=A%2B270\"
\n" ); document.write( "\"%28L%2B5%29%28W%2B2%29=5L%2B270\"
\n" ); document.write( "\"%28L%2B5%29%284L%2B2%29=5L%2B270\"
\n" ); document.write( "\"%284L%5E2%2B20L%2B2L%2B8%29=5L%2B270\"
\n" ); document.write( "\"4L%5E2%2B22L-5L%2B8-270=0\"
\n" ); document.write( "\"4L%5E2%2B17L-262=0\"
\n" ); document.write( "use the quadratic formula to solve for L, below is the solver to show steps, but for now \"L=6.24\"or\"L=-10.49\" but the lengths cant be negative so \"L=6.24\"
\n" ); document.write( "now we can find all the other lengths of the 2 rectangles
\n" ); document.write( "first rectangle:
\n" ); document.write( "\"A=LW\"
\n" ); document.write( "\"A=6.24%2824.96%29\"
\n" ); document.write( "\"A=155.7504\"
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\n" ); document.write( "\"W=4L\"
\n" ); document.write( "\"W=4%286.24%29\"
\n" ); document.write( "\"W=24.96\"
\n" ); document.write( "___________
\n" ); document.write( "\"X=L%2B5\"
\n" ); document.write( "\"X=%286.24%29%2B5\"
\n" ); document.write( "\"X=11.24\"
\n" ); document.write( "___________
\n" ); document.write( "\"Y=W%2B2\"
\n" ); document.write( "\"Y=%2824.96%29%2B2\"
\n" ); document.write( "\"Y=26.96\"\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aL%5E2%2BbL%2Bc=0\" (in our case \"4L%5E2%2B17L%2B-262+=+0\") has the following solutons:
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\n" ); document.write( " \"L%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2817%29%5E2-4%2A4%2A-262=4481\".
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\n" ); document.write( " Discriminant d=4481 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-17%2B-sqrt%28+4481+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"L%5B1%5D+=+%28-%2817%29%2Bsqrt%28+4481+%29%29%2F2%5C4+=+6.24253398558978\"
\n" ); document.write( " \"L%5B2%5D+=+%28-%2817%29-sqrt%28+4481+%29%29%2F2%5C4+=+-10.4925339855898\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"4L%5E2%2B17L%2B-262\" can be factored:
\n" ); document.write( " \"4L%5E2%2B17L%2B-262+=+4%28L-6.24253398558978%29%2A%28L--10.4925339855898%29\"
\n" ); document.write( " Again, the answer is: 6.24253398558978, -10.4925339855898.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+4%2Ax%5E2%2B17%2Ax%2B-262+%29\"

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