document.write( "Question 285614: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle?\r
\n" );
document.write( "\n" );
document.write( "I would like to see how to solve the problem in steps, if possible. Thank you! \n" );
document.write( "
Algebra.Com's Answer #207047 by JBarnum(2146)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "so now wee need to substitute to be able to solve for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "use the quadratic formula to solve for L, below is the solver to show steps, but for now \n" ); document.write( "now we can find all the other lengths of the 2 rectangles \n" ); document.write( "first rectangle: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |