document.write( "Question 285611: If the sides of a square are lenghtened by 8 cm, the area
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\n" ); document.write( "\n" ); document.write( "The length of a side of the original square is ------- cm.
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Algebra.Com's Answer #207018 by Theo(13342)\"\" \"About 
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formula for area of a square is:\r
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\n" ); document.write( "\n" ); document.write( "a = x^2\r
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\n" ); document.write( "\n" ); document.write( "Increase the side by 8 cm and the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "144 = (x+8)^2\r
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\n" ); document.write( "\n" ); document.write( "You want to find the length of the side of the original square, which is x.\r
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\n" ); document.write( "\n" ); document.write( "(x+8)^2 = x^2 + 16x + 64\r
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\n" ); document.write( "\n" ); document.write( "Equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "144 = x^2 + 16x + 64\r
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\n" ); document.write( "\n" ); document.write( "Subtract 144 from both sides of this equation to get\r
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\n" ); document.write( "\n" ); document.write( "0 = x^2 + 16x - 80\r
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\n" ); document.write( "\n" ); document.write( "This factors out to be:\r
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\n" ); document.write( "\n" ); document.write( "0 = (x+20) * (x-4)\r
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\n" ); document.write( "\n" ); document.write( "You get x = -20 or x = 4\r
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\n" ); document.write( "\n" ); document.write( "x can't be negative so x has to be 4.\r
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\n" ); document.write( "\n" ); document.write( "When x = 4, the area is 4^2 = 16
\n" ); document.write( "When x = 4 + 8 = 12, the area is 12^2 = 144\r
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\n" ); document.write( "\n" ); document.write( "Numbers check out so answer is that the side of the original square is 4 cm.\r
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