document.write( "Question 285588: What's the domain of f+g when f(x)=2x-5 and g(x)= square root x+6 \n" ); document.write( "
Algebra.Com's Answer #207016 by Theo(13342)\"\" \"About 
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(f+g)(x) = f(x) + g(x)\r
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\n" ); document.write( "\n" ); document.write( "f(x) = 2x-5
\n" ); document.write( "g(x) = sqrt(x+6)\r
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\n" ); document.write( "\n" ); document.write( "(f+g)(x) = (2x-5) + sqrt(x+6)\r
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\n" ); document.write( "\n" ); document.write( "The only restriction on the domain of this function is the square root of (x+2^ can't be negative.\r
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\n" ); document.write( "\n" ); document.write( "to find out when sqrt(x+6) goes negative, use the equation:\r
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\n" ); document.write( "\n" ); document.write( "(x+6) < 0\r
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\n" ); document.write( "\n" ); document.write( "Subtract x from this equation to get x < -6\r
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\n" ); document.write( "\n" ); document.write( "When x < -6, the square root of (x+6) goes negative and the domain goes invalid.\r
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\n" ); document.write( "\n" ); document.write( "The domain of (f+g)(x) is therefore all values of x >= -6\r
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\n" ); document.write( "\n" ); document.write( "Note that this i also the domain of g(x).\r
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\n" ); document.write( "\n" ); document.write( "The domain of f(x) is all real value of x.\r
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\n" ); document.write( "\n" ); document.write( "(f+g)(x) adds f(x) plus g(x) together so the domain becomes the more restrictive of the two which is the domain of g(x).\r
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\n" ); document.write( "\n" ); document.write( "A graph of the equation (f+g)(x) = (2x-5) + sqrt(x+6) is shown below:\r
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\n" ); document.write( "\n" ); document.write( "\"graph+%28400%2C400%2C-10%2C10%2C-20%2C20%2C%282x-5%29+%2B+sqrt%28x%2B6%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can see that the graph stops at x = -6 and doesn't go any further.\r
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\n" ); document.write( "\n" ); document.write( "That's because the value of y when x < -6 is not a real number and is therefore undefined.\r
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