document.write( "Question 4464: solve for y: 24y +11 sqrt of y -18=0 \n" ); document.write( "
Algebra.Com's Answer #2070 by pushpaharan(47)![]() ![]() ![]() You can put this solution on YOUR website! let sqrt of y =x \n" ); document.write( "24x^2+11x-18 =0 \n" ); document.write( "(8x+9)(3x-2)=0 \n" ); document.write( "x= -9/8 or x= 2/3 \n" ); document.write( "therfore y = 81/64 or y= 4/9 \n" ); document.write( " |