document.write( "Question 285491: 4x+y-z=8
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document.write( "x-y+2z=3
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document.write( "3x-y+z=6\r
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document.write( "I am not even sure where to start with this problem.... \n" );
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Algebra.Com's Answer #206974 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 4x+y-z=8 add equations 1 & 3 \n" ); document.write( "x-y+2z=3 \n" ); document.write( "3x-y+z=6 \n" ); document.write( "4x+y-z=8 \n" ); document.write( "---------- \n" ); document.write( "7x=14 \n" ); document.write( "x=14/2 \n" ); document.write( "x=2 ans. \n" ); document.write( "Replace x with 2 in equation 2 & 3 \n" ); document.write( "2-y+2z=3 \n" ); document.write( "-y+2z=3-2 \n" ); document.write( "-y+2z=1 subtract this equation from the last equation. \n" ); document.write( "3*2-y+z=6 \n" ); document.write( "6-y+z=6 \n" ); document.write( "-y+z=6-6 \n" ); document.write( "-y+z=0 \n" ); document.write( "-(-y+2z=1) \n" ); document.write( "-------------- \n" ); document.write( "-z=-1 \n" ); document.write( "z=1 ans. \n" ); document.write( "4*2+y-1=8 \n" ); document.write( "8+y-1=8 \n" ); document.write( "y=8-8+1 \n" ); document.write( "y=1 ans. \n" ); document.write( "x,y,z (2,1,1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |