document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285535>Question 285535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a line passes through the point (-8,4) and is perpendicular to the line y =-3x + 2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206962 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-8,4) and is perpendicular to the line <BR>\n" );
document.write( "y=-3x+2 (red line)<BR>\n" );
document.write( "This line has a slope=-3.<BR>\n" );
document.write( "A perpendicular line will have a slope=1/3.<BR>\n" );
document.write( "Y=mX+b is the standard line equation where m=slope & b=the Y intercept.<BR>\n" );
document.write( "4=1/3*-8+b<BR>\n" );
document.write( "4=-8/3+b<BR>\n" );
document.write( "b=4+8/3<BR>\n" );
document.write( "b=(12+8)/3<BR>\n" );
document.write( "b=20/3 the Y intercept.<BR>\n" );
document.write( "Y=x/3+20/3 (green line)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-3x+%2B2%2C+x%2F3+%2B20%2F3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-3x+%2B2%2C+x%2F3+%2B20%2F3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -3x +2 and x/3 +20/3). <BR>\n" );
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