document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285515>Question 285515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 25% solution must be mixed with 60 gallons of a 50% solution to get a 30% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206956 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of gal of 25% solution needed\r<BR>\n" );
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document.write( "Now we know that the amount of \"pure stuff\" in the 25% solution (0.25x) plus the amount of \"pure stuff\" in the 60 gal of the 50% solution ((0.50*60) has to equal the amount of \"pure stuff\" in the final mixture (0.30(60+x)).  So, our equation to solve is:\r<BR>\n" );
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document.write( "0.25x+0.50*60=0.30(60+x)  get rid of parens and simplify<BR>\n" );
document.write( "0.25x+30=18+0.30x  subtract 0.25x and also 18 from each side<BR>\n" );
document.write( "30-18=0.30x-0.25x<BR>\n" );
document.write( "0.05x=12  divide each side by 0.05<BR>\n" );
document.write( "x=240 gal of 25% solution is needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "240*0.25 +0.50*60=0.30*300<BR>\n" );
document.write( "60+30=90<BR>\n" );
document.write( "90=90\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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