document.write( "Question 285529: How many positive integers below 2009 are divisible by both 4 and 6?\r
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document.write( "A. 502 B. 334 C. 167 D. 83 E. None of these. \n" );
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Algebra.Com's Answer #206947 by Theo(13342)![]() ![]() You can put this solution on YOUR website! 4 goes into 2009 502.2 times. \n" ); document.write( "6 goes into 2009 334.833333 times. \n" ); document.write( "The least common multiple of 4 and 6 appears to be 12. \n" ); document.write( "This is because 3*4 = 12 and 2*6 = 12. \n" ); document.write( "12 goes into 2009 167.4166667 times. \n" ); document.write( "Round that down to the nearest integer and you get 167.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I believe that's your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In between those numbers, 4 and 6 do not both divide into the numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you go up by 4 from 1 to 48, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4,8,12,16,20,24,28,32,36,40,44,48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you go up by 6 from 1 to 48, you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6,12,18,24,30,36,42,48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The common numbers are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12,24,36,48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These are the numbers that are divisible by both 4 and 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice they are all multiples of 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your answer is selection C (167).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |