document.write( "Question 34369: A university bookstore recently sold a wirebound graph-paper notebook for $2.50, and a college-ruled notebook for $2.30. At the start of spring semester, a combination of 50 of these notebooks were sold for a total of $118.60. How many of each type were sold? \n" ); document.write( "
Algebra.Com's Answer #20690 by usyim88hk(158)\"\" \"About 
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We can use Substitution to work on this problem:
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\n" ); document.write( "Let x be the number of wirebound graph-paper notebook
\n" ); document.write( "Let y be the number of college-ruled notebook
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\n" ); document.write( "So we now have an equation
\n" ); document.write( "x + y = 50
\n" ); document.write( "since the numbers of this two kinds of notebook add up to 50
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\n" ); document.write( "now we can make another equation
\n" ); document.write( "2.5x + 2.3y = 118.6
\n" ); document.write( "~
\n" ); document.write( "2.5x means the earning of the sold wirebound graph-paper notebooks
\n" ); document.write( "2.3y means the earning of the sold college-ruled notebooks
\n" ); document.write( "and they add up to 118.6
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\n" ); document.write( "Now we can solve for x
\n" ); document.write( "x + y = 50
\n" ); document.write( "x = 50 - y
\n" ); document.write( "~
\n" ); document.write( "Now substitute x into the other equation
\n" ); document.write( "2.5x + 2.3y = 118.6
\n" ); document.write( "2.5 (50 - y) + 2.3y = 118.6
\n" ); document.write( "(x is equal to 50 - y so the x in the second equation become 50-y)
\n" ); document.write( "~
\n" ); document.write( "Now solve for y
\n" ); document.write( "2.5 (50 - y) + 2.3y = 118.6
\n" ); document.write( "125 - 2.5y + 2.3y = 118.6
\n" ); document.write( "125 - 0.2y = 118.6
\n" ); document.write( "125 = 118.6 + 0.2y
\n" ); document.write( "6.4 = 0.2y
\n" ); document.write( "y = 32
\n" ); document.write( "So the total numebr of sold college-ruled notebooks is 32, while the total number of sold wirebound graph-paper notebooks is 50 - 32 = 18
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