document.write( "Question 285425: Having issues solving this one: (x-5)²-6(x-5)+8. I came up with the answer (x-11)(x+3) but that's not the right answer...please help. Used the u²+bu+c formula and Im missing something here. \n" ); document.write( "
Algebra.Com's Answer #206895 by richwmiller(17219)\"\" \"About 
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\n" ); document.write( "let's say u= (x-5)
\n" ); document.write( "u^2-6u+8
\n" ); document.write( "factors are -4 and -2
\n" ); document.write( "(u-4)*(u-2)
\n" ); document.write( "now substitute x-5 for u
\n" ); document.write( "(x-5-4)*(x-5-2)
\n" ); document.write( "(x-9)*(x-7)
\n" ); document.write( "Which works.
\n" ); document.write( "I can't for the life of me think how you got (x-11) and (x+3).\r
\n" ); document.write( "\n" ); document.write( "if you had calculated out the original expression you should have gotten
\n" ); document.write( "x^2-16x+63
\n" ); document.write( "which also factors to (x-9)(x-7)
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