document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285168>Question 285168</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a triangle has an angle A of 50 degrees, B at 65 degrees, and a= 12, what is the measures of side c and b? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206893 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a triangle has an angle A of 50 degrees, B at 65 degrees, and a= 12, what is the measures of side c and b?<BR>\n" );
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document.write( "Use the Law of Sines:<BR>\n" );
document.write( "b/sin(65) = 12/sin(50)<BR>\n" );
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document.write( "b = sin(65)[12/sin(50)]<BR>\n" );
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document.write( "b = 14.197<BR>\n" );
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document.write( "Angle C = 180-(50+65) = 75 degrees<BR>\n" );
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document.write( "c/sin(75) = 12/sin(50)<BR>\n" );
document.write( "c = sin(75)<BR>\n" );
document.write( "c = 15.13<BR>\n" );
document.write( "==================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );