document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285400>Question 285400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP!! <BR>\n" );
document.write( "1. If sin(theta)=1/2, then sin(-theta)=______, sin(pi - theta)=______, and sin(theta + pi)=________?<BR>\n" );
document.write( "2. If cos(theta)=square root 3/2, then cos(-theta)=______, cos(pi - theta)=_____, and cos (theta + pi)=______ ?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206882 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. If sin(theta)=1/2, then sin(-theta)= -1/2,<BR>\n" );
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document.write( "sin(pi - theta)= sin(pi)cos(theta)-cos(pi)sin(theta) = 0-(-1)(1/2) = 1/2<BR>\n" );
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document.write( "sin(theta + pi)= sin(theta)cos(pi)+cos(theta)sin(pi) = -sin(theta)+0 = -1/2<BR>\n" );
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document.write( "2. If cos(theta)=(sqrt3)/2, then cos(-theta)=(sqrt3)/2,<BR>\n" );
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document.write( "cos(pi - theta)= cos(pi)cos(theta)+sin(pi)sin(theta)= -cos(theta)= -(sqrt3)/2<BR>\n" );
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document.write( "cos(theta+pi)=cos(theta)cos(pi)-sin(theta)sin(pi)=-cos(theta)= -(sqrt3)/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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