document.write( "Question 285377: what is the volume of the region inside a 6 inch cube but outside the sphere? \n" ); document.write( "
Algebra.Com's Answer #206874 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! what is the volume of the region inside a 6 inch cube but outside the sphere? \n" ); document.write( "------------ \n" ); document.write( "Find the diagonal of the cube: \n" ); document.write( "--- \n" ); document.write( "hypotenuse of a face: 6*sqrt(2) \n" ); document.write( "------ \n" ); document.write( "diagonal = sqrt(6^2 + (6sqrt(2))^2) \n" ); document.write( "diagonal = sqrt(36 + 72) \n" ); document.write( "diagonal = 6sqrt(3) \n" ); document.write( "--- \n" ); document.write( "Therefore the radius of the sphere = (1/2)diagonal = 3sqrt(3) \n" ); document.write( "--------------------------------- \n" ); document.write( "So the volume of the sphere = (4/3)(pi)(3sqrt(3))^3 \n" ); document.write( "------------------------------------ \n" ); document.write( "The volume of the cube = 6^3 = 216 \n" ); document.write( "======================================= \n" ); document.write( "Volume within the sphere but outside the cube \n" ); document.write( "= (4/3)pi(3sqrt(3)^3 - 216 \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |