document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285289>Question 285289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I could really use your help today, I am stuck. \r<BR>\n" );
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document.write( "x/x-2=1/2-x+2/x<BR>\n" );
document.write( "2x(x)/2x(x-2)=x(x-2)/2x(x-2)-2(x-2)(x+2)/2x(x-2)<BR>\n" );
document.write( "2x^2/2x(x-2)=x^2-2x/2x(x-2)-x^2+8/2x(x-2)\r<BR>\n" );
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document.write( "I am lost from here as the last term numerator is negative. I must have made a wrong turn along the way. I appreciate your help.\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Tina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206867 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/(x-2)=1/2-(x+2)/x\r<BR>\n" );
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document.write( "2x(x-2)[x/(x-2)]=2x(x-2)[1/2]-2x(x-2)[(x+2)/x]\r<BR>\n" );
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document.write( "2x^2=x(x-2)-2(x-2)(x+2)\r<BR>\n" );
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document.write( "2x^2=x^2-2x-2x^2+8\r<BR>\n" );
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document.write( "3x^2+2x-8=0\r<BR>\n" );
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document.write( "(x+2)(3x-4)=0\r<BR>\n" );
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document.write( "x=-2 or x=4/3 <--------------- Answers </SPAN>\n" );
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