document.write( "Question 285330: A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level. \n" ); document.write( "
Algebra.Com's Answer #206848 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A department store manager claims that at least 45% of persons who visited this store make a purchase. In a sample of 400 persons who visited the store 150 made a purchase. Test the manager’s claim at the 3% significance level. \n" ); document.write( "----------------------------------- \n" ); document.write( "Ho: p >= 0.45 (manager's claim) \n" ); document.write( "Ha: p < 0.45 \n" ); document.write( "------------------- \n" ); document.write( "sample proportion: 150/400 = 0.375 \n" ); document.write( "--- \n" ); document.write( "test stat: z(0.375) = (0.375-0.45)/sqrt[0.45*0.55/400] \n" ); document.write( "= -3.015 \n" ); document.write( "--- \n" ); document.write( "Critical Value for left-tail test with alpha=3% \n" ); document.write( "is z = invNorm(0.03) = -1.8808 \n" ); document.write( "--------------- \n" ); document.write( "Conclusion: \n" ); document.write( "Since the test statistic is in the reject interval \n" ); document.write( "reject Ho, which is the manager's claim. \n" ); document.write( "============================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |