document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=276953>Question 276953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Exactly how many degrees are there between the hands of a clock at 3:40 pm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206833 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Exactly how many degrees are there between the hands of a clock at 3:40 pm<BR>\n" );
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document.write( "Measuring clockwise (what else?) from the 12, the minute hand is at 240 degs.<BR>\n" );
document.write( "The hour hand is at 360*(3 2/3)/12 = 30*(11/3) = 110 degs.<BR>\n" );
document.write( "The angle between them is 240 - 110 = 130 degrees.<BR>\n" );
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document.write( "Here's a simpler method.<BR>\n" );
document.write( "The minute hand is 2/3 of a revolution = 240 degs.<BR>\n" );
document.write( "The hour hand is at 3, = 90 degs + 2/3 of 30 degs.  The hour hand moves 30 degs/hr, so it's 20 degs past the 3.<BR>\n" );
document.write( "--> the hour hand is at 110 degs<BR>\n" );
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document.write( "General solution:<BR>\n" );
document.write( "The angle clockwise from the hour hand to the minute hand is:<BR>\n" );
document.write( "360*min/60 - (hr*30 + 30*(min/60))<BR>\n" );
document.write( "= 11*min/2 - 30*hr<BR>\n" );
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