document.write( "Question 285172: I am a 2 digit number. The difference between the product of me and myself and the sum of me and myself is 99. What number am i? \n" ); document.write( "
Algebra.Com's Answer #206819 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=tens digit
\n" ); document.write( "And let y=units digit
\n" ); document.write( "The number then is 10x+y
\n" ); document.write( "Product of me and myself=(10x+y)*(10x+y)
\n" ); document.write( "The sum of me and myself=(10x+y)+(10x+y)=2(10x+y)
\n" ); document.write( "So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "(10x+y)^2-2(10x+y)=99 subtract 99 from each side
\n" ); document.write( "(10x+y)^2-2(10x+y)-99=0 quadratic in standard form and it can be factored
\n" ); document.write( "{(10x+y)-11}{(10x+y)+9}=0
\n" ); document.write( "10x+y=11---------------------answer
\n" ); document.write( "10x+y=-9-----------------no good, not a 2 digit number
\n" ); document.write( "So the 2 digit number is 11\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "11*11=121
\n" ); document.write( "11+11-22
\n" ); document.write( "121-22=99
\n" ); document.write( "99=99
\n" ); document.write( "Hope this helps---ptaylor
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