document.write( "Question 285263: Wite the equation of a line through the point (-6,3) parallel and perpendicular to the line 2x+3y=1. \n" ); document.write( "
Algebra.Com's Answer #206816 by stanbon(75887)\"\" \"About 
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Wite the equation of a line through the point (-6,3) parallel and perpendicular to the line 2x+3y=1.
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\n" ); document.write( "Put the given equation in slope-intercept form:
\n" ); document.write( "y = (-2/3)x+(1/3)
\n" ); document.write( "slope = -2/3
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\n" ); document.write( "Any parallel line must have slope = -2/3
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\n" ); document.write( "Any perpendicular line must have slope = 3/2
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\n" ); document.write( "Equation of the parallel line thru (-6,-3)
\n" ); document.write( "-3 = (-2/3)(-6) + b
\n" ); document.write( "-3 = 4 + b
\n" ); document.write( "b = -7
\n" ); document.write( "Equation: y = (-2/3)x-7
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\n" ); document.write( "Equation of the perpendicular line thru (-6,-3):
\n" ); document.write( "-3 = (3/2)(-6) + b
\n" ); document.write( "-3 = -9 + b
\n" ); document.write( "b = 6
\n" ); document.write( "Equation: y = (3/2)x+6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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