document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34425>Question 34425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bricklayer and an electrician together spend 90 hours working on a new house. If the bricklayer earns $12 per hour, the electrician earns $16 an hour, and the owner pays them a total of $1350 for their work, how many hours does each worker spend on the house? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20677 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> B+E=90 & 12B+16E=1350 THUS B=90-E SUBSTITUTING 90-E FOR B IN THE SECOND EQUATION WE GET\r<BR>\n" );
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document.write( "12(90-E)+16E=1350 OR 1080-12E+16E=1350 OR 4E=270 OR E=270/4 OR E=67.5 HOURS <BR>\n" );
document.write( "THUS B WORKED 90-67.5 HOURS OR 22.5 HOURS PROOF\r<BR>\n" );
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document.write( "12*22.5+67.5*16=1350 OR 270+1080=1350 OR 1350=1350 </SPAN>\n" );
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