document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=285010>Question 285010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tge hypotenuse of a right triangle measures 10cm. One leg is 2 cm shorter than the other. What are the lengths of the legs? Use the quadratic formula. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206752 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one leg be x\r<BR>\n" );
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document.write( "the other leg = x-2\r<BR>\n" );
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document.write( "x^2 + (x-2)^2= 10^2\r<BR>\n" );
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document.write( "x^2+x^2-4x+4=100\r<BR>\n" );
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document.write( "2x^2-4x-96=0  divide equation by 2\r<BR>\n" );
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document.write( "x^2-2x-48=0\r<BR>\n" );
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document.write( "x^2-8x+6x-48=0\r<BR>\n" );
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document.write( "x(x-8)+6(x-8)=0\r<BR>\n" );
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document.write( "(x-8)(x+6)=0\r<BR>\n" );
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document.write( "x=8 0r -6\r<BR>\n" );
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document.write( "So x is 8 which is a positive value </SPAN>\n" );
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