document.write( "Question 285118: Andrew invested a total of P18,000, part at 5% and part at 9%. If his income for one year from the 9% investment was P100 less than his income from the 5% investment, how much was invested at each rate?
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Algebra.Com's Answer #206732 by mananth(16946)\"\" \"About 
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Andrew invested a total of P18,000, part at 5% and part at 9%. If his income for one year from the 9% investment was P100 less than his income from the 5% investment, how much was invested at each rate?
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\n" ); document.write( "\n" ); document.write( "let him invest x at 5%\r
\n" ); document.write( "\n" ); document.write( "Interest obtained for 1 year will be 5/100 * x\r
\n" ); document.write( "\n" ); document.write( "He will invest 18000-x at9%\r
\n" ); document.write( "\n" ); document.write( "Interest obtained for 1 year will be (18000-x)*9/100\r
\n" ); document.write( "\n" ); document.write( "(18000-x)*9/100=5/100 *x -100\r
\n" ); document.write( "\n" ); document.write( "162000-9x /100 = 5x-10000 /100\r
\n" ); document.write( "\n" ); document.write( "162000-9x=5x-10000\r
\n" ); document.write( "\n" ); document.write( "14x= 172000\r
\n" ); document.write( "\n" ); document.write( "x=12285.7 @ 5%\r
\n" ); document.write( "\n" ); document.write( " 18000-12285.7=5714.3 at9%\r
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