document.write( "Question 285119: 5. Mrs. Santos invested part of P35,000 in a stock paying 9% interest for 2 years and the balance in a stock paying 6% interest for 4 years. It turns out that the two investments earned equal interest. How much was invested at each rate? with a solution and answer plz \n" ); document.write( "
Algebra.Com's Answer #206724 by mananth(16946) You can put this solution on YOUR website! Mrs. Santos invested part of P35,000 in a stock paying 9% interest for 2 years and the balance in a stock paying 6% interest for 4 years. It turns out that the two investments earned equal interest. How much was invested at each rate? with a solution and answer plz\r \n" ); document.write( "\n" ); document.write( "Let the amount invested at9% be x\r \n" ); document.write( "\n" ); document.write( "The balnace 35000-x will be invested at 6%\r \n" ); document.write( "\n" ); document.write( "Interest at 9% will yield an interest = x*2*9 /100 for 2 years\r \n" ); document.write( "\n" ); document.write( "Interest at 6% will yield an interest = (35000-x)*4*6 / 100 for 4 years\r \n" ); document.write( "\n" ); document.write( "The interests are same\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x*2*9 /100 = (35000-x)*4*6/100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "18x*100 / 100 = 840 000 -24x\r \n" ); document.write( "\n" ); document.write( "18x+24x=840 000\r \n" ); document.write( "\n" ); document.write( "42x=840 000\r \n" ); document.write( "\n" ); document.write( "x=840000/42\r \n" ); document.write( "\n" ); document.write( "x=20000\r \n" ); document.write( "\n" ); document.write( "35000-20000=15000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "$20000 was invested at 9%\r \n" ); document.write( "\n" ); document.write( "$15000 was invested @ 6%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |