document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34375>Question 34375</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On the first day of school, the percentage of boys in a particular class is 60%. During the school year, six girls move away, and are replaced in the class by six boys; this makes the class roster 75% boys. Find the number of boys and girls in the class on the first day of school. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20671 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b=.6t b=boys t=total number in class<BR>\n" );
document.write( "b+6=.75t substituting .6t for b in the second equation we get<BR>\n" );
document.write( ".6t+6=.75t ot 6=.15t or t=6/.15 or t=40 therefore .6*40=boys or .6*40=24 boys and 16 girls (40-24) at the beginning of school.\r<BR>\n" );
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document.write( "24+6=30 OR .75*40=30   </SPAN>\n" );
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