document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34376>Question 34376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Walt made an extra $9000 last year from a part-time job. He invested part of the money at a 9% annual rate of interest, and the rest at an 8% annual rate of interest. At the end of the year, he made a total of $770 in interest. How much was invested at 8%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20670 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (9000-x).08+.09x=770 or 720-.08x+.09x=770 or .01x=50 or x=5000 thus the amount invested @ 8% is 9000-5000 or 4000 </SPAN>\n" );
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