document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34362>Question 34362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would really appreciate if someone could help me these are the only problems that i didnt know how to do if someone could help me i would appreciate it \r<BR>\n" );
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document.write( "Solving Exponential Equations Using Logarithms round to  3 decimal place\r<BR>\n" );
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document.write( "2x = 30\r<BR>\n" );
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document.write( "5x - 1 = 3x\r<BR>\n" );
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document.write( "3.53x + 1 = 65.4\r<BR>\n" );
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document.write( "16x - 4 = 33 - x\r<BR>\n" );
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document.write( "7x - 2 = 5x<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20668 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x = 30 <BR>\n" );
document.write( "=> log(2x) = log(30)<BR>\n" );
document.write( "=> log 2 + log x = log 30<BR>\n" );
document.write( "=> log x = log 2 - log 30 = log (2/30) = log (1/15)<BR>\n" );
document.write( "=> x = 1/15 = .067<BR>\n" );
document.write( "Follow the same procedure as above to solve the rest of the problems.  Shoot an email if you have difficulties. </SPAN>\n" );
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