document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284968>Question 284968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of each figure described:<BR>\n" );
document.write( "a square with diagonal 4cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206664 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to find the area we need to know the s^2<BR>\n" );
document.write( "to find the ^2 we use the pythagorean theorem since the diagonal will be the hypotenuse.<BR>\n" );
document.write( "2s^2=4^2<BR>\n" );
document.write( "2s^2=16<BR>\n" );
document.write( "s^2=8<BR>\n" );
document.write( "area=s^2=8<BR>\n" );
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