document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34405>Question 34405</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395937760/algebrahomeworkh>Algerbra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I dont understand how to get the answer could you PLEAZZZ explain it:\r<BR>\n" );
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document.write( "-x(to the second)-4x=3\r<BR>\n" );
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document.write( "-x(to the second)+14x=48\r<BR>\n" );
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document.write( "2x(to the second)+7x=-3\r<BR>\n" );
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document.write( "3x(to the second)-5=-14x<BR>\n" );
document.write( "(pg 806) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20666 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x~2-4x-3=0 or x~2+4x+3=0 (multiply all terms by -1) now factor<BR>\n" );
document.write( "(x+3)(x+1)=0 or x=-3 & x=-1\r<BR>\n" );
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document.write( "-x~2+14x-48=0 or x~2-14x+48=0 or (x-6)(x-8)=0 or x=6 & x=8\r<BR>\n" );
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document.write( "2x~2+7x+3=0 or (2x+1)(x+3)=0 or x=-1/2 & x=-3\r<BR>\n" );
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document.write( "3x~2+14x-5=0 or (3x-1)(x+5)=0 or x=1/3 & x=-5 </SPAN>\n" );
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