document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34402>Question 34402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the slope  of a line parallel to each line.<BR>\n" );
document.write( "1.y=2x-3 2.8y=-7x+16 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20660 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The slope for the first equation is 2. using the standard form y=mx+b where the m=slope.\r<BR>\n" );
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document.write( "The qecond equation needs to be changed to the standard slope form  thus<BR>\n" );
document.write( "2.8y=-7x+18 or y=(-7x+18)/2.8 or y=-7/2.8x+18/2.8 or y=-2.5+6.43 or this slope is -2.5.\r<BR>\n" );
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document.write( "Any line with a slope of 2 or -2.5 is parallel to these lines.  </SPAN>\n" );
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