document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284786>Question 284786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter oa a cross section or end of a \"two-by-four\" piece of lumber is 10 in. The lengt is 2 in. more than the width. Find the actual dimensions of the cross section of a  two-by-four. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206592 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a cross section or end of a \"two-by-four\" piece of lumber is 10 in. The length is 2 in. more than the width. <BR>\n" );
document.write( "Find the actual dimensions of the cross section of a two-by-four.<BR>\n" );
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document.write( "Perimeter = 2(W + L)<BR>\n" );
document.write( "10 = 2(W + (W+2))<BR>\n" );
document.write( "5 = 2W+2<BR>\n" );
document.write( "2W = 3<BR>\n" );
document.write( "Width = 1.5\"<BR>\n" );
document.write( "Length = 1.5+2 = 3.5\"<BR>\n" );
document.write( "==========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );