document.write( "Question 284715: the line passes thru (4,-7) and is perpendicular to the line whose equation is x-2y=3\r
\n" ); document.write( "\n" ); document.write( "write an equation in slope intercept form satisfying the given conditions \n" ); document.write( "

Algebra.Com's Answer #206571 by eggsarecool(46) $\"\"$ $\"About$

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The first step in such a problem is to solve the given equation for y.
\n" ); document.write( " $\"x-2y=3\"$ So subtract x from both sides.
\n" ); document.write( " $\"-2y=3-x\"$ Now divdie everything by -2.
\n" ); document.write( " $\"y=-3%2F2+%2B+%281%2F2%29%2Ax\"$ The number attached to the x is the slope of this line, $\"1%2F2\"$ To get a line that is perpendicular you need to take the negative reciprocal which would be $\"-2%2F1\"$ or just -2.
\n" ); document.write( "We now do $\"y=mx%2Bb\"$ m stands for slope so we have.
\n" ); document.write( " $\"y=-2x%2Bb\"$ Now you plug in (4,-7), 4 for x and -7 for y to get the line that passes through that point and solve for b.
\n" ); document.write( " $\"-7=-2%2A4%2Bb\"$
\n" ); document.write( " $\"-7=-8%2Bb\"$ add 8 to both sides.
\n" ); document.write( " $\"1=b\"$
\n" ); document.write( "Going back to $\"y=-2x%2Bb\"$ you will now put in the b you found.
\n" ); document.write( "And $\"y=-2x%2B1\"$ is your final answer. \n" ); document.write( "

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