document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284612>Question 284612</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the area of a circle is pie(2x squared+16x+7) what is the radius? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206563 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206563\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of a circle is equal to pi*r^2.\r<BR>\n" );
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document.write( "if the area of a circle is also equal to pi * (2x^2 + 16x + 7), this means that:\r<BR>\n" );
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document.write( "pi*r^2 = pi*(2x^2 + 16x + 7).\r<BR>\n" );
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document.write( "divide both sides of this equation by pi and you get:\r<BR>\n" );
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document.write( "r^2 = (2x^2 + 16x + 7)\r<BR>\n" );
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document.write( "take the square root of both sides of this equation and you get:\r<BR>\n" );
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document.write( "r = +/- sqrt(2x^2 + 16x + 7)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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