document.write( "Question 284724: The radius of a cylinder is increased by 40%, but the height is cut in half.
\n" ); document.write( "What is the resulting change in volume?\r
\n" ); document.write( "\n" ); document.write( "A.2% decrease B. 30% decrease C. 30% increase D. 2% increase
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #206562 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The radius of a cylinder is increased by 40%, but the height is cut in half.
\n" ); document.write( "What is the resulting change in volume?\r
\n" ); document.write( "\n" ); document.write( "A.2% decrease B. 30% decrease C. 30% increase D. 2% increase
\n" ); document.write( "--------------------
\n" ); document.write( "\"V+=+pi%2Ar%5E2%2Ah\"
\n" ); document.write( "The radius is multiplied by 1.4. The radius in the formula is squared, so the volume is multiplied by 1.4^2 = 1.96
\n" ); document.write( "-----------------
\n" ); document.write( "The height is multiplied by 0.5, and it's to the first power, so the volume is directly related to h.
\n" ); document.write( "--------------
\n" ); document.write( "Volume is multiplied by 1.96*0.5 = 0.98
\n" ); document.write( "That's a 2% reduction
\n" ); document.write( "A
\n" ); document.write( "---------
\n" ); document.write( "Another tutor got the same numbers, but used the \"after\" volume as a reference. The original volume should be used as the reference.
\n" ); document.write( "
\n" );