document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284734>Question 284734</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried to work this problem can you please help me.\r<BR>\n" );
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document.write( "                  2x<3y + 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206559 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equation is:\r<BR>\n" );
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document.write( "2x < 3y + 6\r<BR>\n" );
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document.write( "You want to solve for y so you can graph this equation.\r<BR>\n" );
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document.write( "first get all the y terms on the left side of the equation and everything else on the right side of the equation.\r<BR>\n" );
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document.write( "you do this in the following manner:\r<BR>\n" );
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document.write( "subtract 3y from both sides of the equation to get:\r<BR>\n" );
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document.write( "-3y + 2x < 6\r<BR>\n" );
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document.write( "subtract 2x from both sides of the equation to get:\r<BR>\n" );
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document.write( "-3y < -2x + 6\r<BR>\n" );
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document.write( "multiply both sides of the equation by -1 to get:\r<BR>\n" );
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document.write( "3y > 2x - 6\r<BR>\n" );
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document.write( "notice that the inequality is reversed when you multiply both sides of this equation by -1.\r<BR>\n" );
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document.write( "divide both sides of this equation by 3 to get:\r<BR>\n" );
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document.write( "y > (2/3)x - 2\r<BR>\n" );
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document.write( "graph the equality equation of y = (2/3)x - 2 to get:\r<BR>\n" );
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document.write( "y will be any value above that line.\r<BR>\n" );
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document.write( "for example, when x = 3, any value of y > 0 will satisfy the equation.\r<BR>\n" );
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document.write( "to confirm, let x = 3 in your original equation.\r<BR>\n" );
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document.write( "your original equation is:\r<BR>\n" );
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document.write( "2x < 3y + 6\r<BR>\n" );
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document.write( "when x is equal to 3, this becomes:\r<BR>\n" );
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document.write( "6 < 3y + 6\r<BR>\n" );
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document.write( "subtract 6 from both sides of this equation to get:\r<BR>\n" );
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document.write( "0 < 3y\r<BR>\n" );
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document.write( "divide both sides of this equation by 3 to get:\r<BR>\n" );
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document.write( "0 < y\r<BR>\n" );
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document.write( "since 0 < y is the same as y > 0, the solution is confirmed.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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