document.write( "Question 34394This question is from textbook College Algebra Essentials
\n" ); document.write( ": I am not sure how to solve this problem when there is a x^3\r
\n" ); document.write( "\n" ); document.write( "x^3 + y = 0
\n" ); document.write( "x^2 - y + 0 \n" ); document.write( "

Algebra.Com's Answer #20655 by checkley71(8403) $\"\"$ $\"About$

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x~3+y=0
\n" ); document.write( "x~2-y=0 adding these two equations we get
\n" ); document.write( "x~3+x~2=0 (the +y & the -y cancel out)
\n" ); document.write( "now we factor x~2 out & we have x~2(x+1)=0 x~2=0 or x=0 and x+1=0 or x=-1
\n" ); document.write( "substituting -1 for x in both equations we get
\n" ); document.write( "(-1)~3+y=0 or -1+y=0 or -1=-y or y=1
\n" ); document.write( "(-1)~2-1=0 or 1-y=0 or 1=y therefore x=-1 & y=1 \n" ); document.write( "

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