document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284674>Question 284674</A>: <I><SPAN STYLE=\"word-break: break-all;\">  find three consecutive intergers such that the sum of three times the middle integer and five times the smaller integer is the same as seven times the larger integer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206536 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be x , x+1, x+2\r<BR>\n" );
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document.write( "3times the middle = 3(x+1)\r<BR>\n" );
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document.write( "5times the smaller =5x\r<BR>\n" );
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document.write( "7 times the largest = 7(x+2)\r<BR>\n" );
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document.write( "3(x+1)+5x=7(x+2)\r<BR>\n" );
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document.write( "3x+3+5x=7x+14\r<BR>\n" );
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document.write( "8x+3=7x+14\r<BR>\n" );
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document.write( "8x-7x=14-3\r<BR>\n" );
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document.write( "x=11\r<BR>\n" );
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document.write( "the numbers are 11 , 12, 13  </SPAN>\n" );
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