document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284705>Question 284705</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Karen walsh has twice as much money invested at 5% simple interest as she does at 4%. If her yearly income from these two investments is $350, how much does she have invested at each rate. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206534 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the amount invested at4% be x\r<BR>\n" );
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document.write( "The amount invested at 5%=2x\r<BR>\n" );
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document.write( "The interest obtained = 350 for 1/2 year  or 700 per year\r<BR>\n" );
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document.write( "0.04x+0.05*2x= 700\r<BR>\n" );
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document.write( "0.04x+0.1x=700<BR>\n" );
document.write( "0.14 x =700\r<BR>\n" );
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document.write( "x=700/0.14\r<BR>\n" );
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document.write( "x=5000 which is the amount invested at4%\r<BR>\n" );
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document.write( "2*5000 = 10000 is the amount invested at5%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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