document.write( "Question 284540: Write in terms of the NATURAL LOG. (ln)
\n" ); document.write( "1. log (base 4)x
\n" ); document.write( "2. log (base 10) (x+1)
\n" ); document.write( "3. log (base 5) x^4
\n" ); document.write( "

Algebra.Com's Answer #206449 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
The formula for converting a logarithm of one base into an expression of logarithms of another base is: \"log%28a%2C+%28p%29%29+=+log%28b%2C+%28p%29%29%2Flog%28b%2C+%28a%29%29\" (Note where the argument and the base of the original logarithm (on the left) end up on the right side.)

\n" ); document.write( "We will use this to convert your logarithms into natural logarithms (aka ln). I'll do the last one first because it is harder than the other two.
\n" ); document.write( "\"log%285%2C+%28x%5E4%29%29\"
\n" ); document.write( "Using the conversion formula on this we get:
\n" ); document.write( "\"ln%28x%5E4%29%2Fln%285%29\"
\n" ); document.write( "This may be an acceptable answer. But we could use a property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", to move the exponent of the argument in the numerator out in front:
\n" ); document.write( "\"4ln%28x%29%2Fln%285%29\"

\n" ); document.write( "The other two problems are just one step. I'll leave them for you to finish. Just use the conversion formula like I did above.
\n" ); document.write( "
\n" );