document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284519>Question 284519</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I would realy appreciate any help I could get with this word problem (step by step).  Could you please also explain how I would check the answer.   Thanks for your time\r<BR>\n" );
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document.write( "Airspeed. A plane carries enough fuel for 20 hours of<BR>\n" );
document.write( "flight at an airspeed of 150 miles per hour. How far can it<BR>\n" );
document.write( "fly into a 30 mile per hour headwind and still have enough<BR>\n" );
document.write( "fuel to return to its starting point? (This distance is called<BR>\n" );
document.write( "the point of no return.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206436 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Flying into the headwind, the ground speed is airspeed minus wind speed, so 150 - 30 is 120.  Flying with a tail wind, the ground speed is airspeed plus wind speed, here: 180 mph.\r<BR>\n" );
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document.write( "Distance equals rate times time.  Let <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\"> represent the time flying into the wind.  Then, since the total trip has to be no more than 20 hours, the time flying home must be <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large 24\ -\ t\">.  And the distance, <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large d\">, out has to be equal to the distance coming back.\r<BR>\n" );
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document.write( "So:\r<BR>\n" );
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document.write( "Outward trip:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ 120t\">\r<BR>\n" );
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document.write( "Return trip:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ 180(20\ -\ t)\">\r<BR>\n" );
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document.write( "But since <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large d\ =\ d\">:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 120t\ =\ 180(20\ -\ t)\">\r<BR>\n" );
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document.write( "Now solve for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\">\r<BR>\n" );
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document.write( "Once you have a value for <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t\">, substitute it into either of the two equations and solve for d.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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