document.write( "Question 284446: The following questions pertain to a rectangle that has a perimeter of 20cm.\r
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document.write( "a) Find the value of x.
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document.write( "Width:
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document.write( "Height: \r
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document.write( "b) Give an expression for the area.\r
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document.write( "Thank you for any help you can offer. \n" );
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Algebra.Com's Answer #206424 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The perimeter = 2 times width + 2 times length \n" ); document.write( "20 = 2(2x - 3) + 2(2x + 3) \r \n" ); document.write( "\n" ); document.write( "20 = 4x - 6 + 4x + 6\r \n" ); document.write( "\n" ); document.write( "20 = 8x\r \n" ); document.write( "\n" ); document.write( "20/8 = x\r \n" ); document.write( "\n" ); document.write( "5/2 = x \n" ); document.write( "=============================================== \r \n" ); document.write( "\n" ); document.write( "The area = width times length \r \n" ); document.write( "\n" ); document.write( "Then A = (2x - 3)(2x + 3) \r \n" ); document.write( "\n" ); document.write( "Area must be written, in this case, in terms of x.\r \n" ); document.write( "\n" ); document.write( "A = 4x^2 + 6x - 6x - 9\r \n" ); document.write( "\n" ); document.write( "A = 4x^2 - 9\r \n" ); document.write( "\n" ); document.write( "Done!\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |